乐山市高中 2025 届期末教学质量检测
物 理(答案)
一、单项选择题
1 2 3 4 5 6 7
B D A C C B A
二、多项选择题
8 9 10
BC AC BD
三、实验题
11.(1)大(1 分)
(2)CD(2 分,漏选得 1 分,错选不得分)
cos
(3) 1(2 分)
cos 2
(4)偏小(2 分)
12.(1)2 0(2 分) (2)
2(2 分)
4 2
(3) (2 分) (4)无(2 分)
四、计算题
13.(12 分)第(1)问 6 分,第(2)问 6 分
解:(1)根据题意画出该单色光在三棱镜中的光路图···················(1 分)
单色光在 AB 边恰好发生全反射,由几何关系可得,
= 37° ······································(1分)
1
已知sin = 可得········································(2 分)
5
= ········································(2 分)
3
(2)由几何关系可得
单色光的三棱镜中的传播距离为 = + = = ·······(1 分)
已知 = 可得···········································(2 分)
3
单色光的三棱镜中的传播速度为 = = ···················(1分)
5
5
单色光的三棱镜中的传播时间为 = = ···················(2 分)
3
14.(14 分)第(1)问 6 分,第(2)问 8 分
解:(1)由波形图可知
{#{QQABCYKEogAAAIBAAAhCUQEqCgCQkBGAAYgOREAIsAAAwRNABAA=}#}
甲 = 9 ······································(1分)
乙 = 4 ······································(1分)
由 = 可得,···········································(2分)
甲 4
= ········································(2 分)
9
乙
(2)振动方程为 = sin(2 + 0) cm,由波形图可知·········(2 分)
绳波乙的振幅 = 25cm···································(1 分)
绳波乙的周期 = ······································(2 分)
平衡位置为 4m 位置处的质点,再过 会运动到负向最大位移处可得
4
25 = 25 sin (2 + 0) ·····················(1 分) 4
0 = ······································(1 分)
所以平衡位置为 4m 位置处的质点的振动方程为:
15
= 25 sin ( + ) cm························(1分)
2
15.(16 分)第(1)问 3 分,第(2)问 4 分,第(3)问 9 分
解:(1)由交流发电机产生电动势的最大值 = 可得··········(2 分)
= 300√2V ································(1 分)
3
(2)用户区的流过电动机的电流 = 4
8.8×10
4 = = 40A············(·1分) 4 220
降压变压器处,由 3 = 4可得,····························(1 分)
4 3
3 = 4A ·····································(1 分)
输电线路上损耗的电功率 = 23 = 160W·················(1 分)
(3)降压变压器处,由 3
= 3可得·······························(1 分)
4 4
3 = 2200V ··································(1 分)
升压变压器处,由 2 = 3 + 3 可得························(1 分)
2 = 2240V ··································(1 分)
由 1
= 1可得, 1 = 280V·································(1 分) 2 2
由 1 = 3可得, 1 = 32A···································(1 分) 2 1
由交流发电机产生的电压有效值为 = = 300V············(1 分)
√2
故交流发电机线圈电阻 r 上损耗的热功率 = 1 1 1 = 640W(1 分)
功率之比为4: 1··········································(1 分)
{#{QQABCYKEogAAAIBAAAhCUQEqCgCQkBGAAYgOREAIsAAAwRNABAA=}#}机密★启用前〔考试时间:2024年7月3日上午9:00一10:15]
乐山市高中2025届期末教学质量检测
物
理
本试题卷共四个大题,共6页,满分100分,考试时间75分钟。考生作答时,须将答案答
在答题卡上,在本试题卷、草稿纸上答题无效。
注意事项:
1.答第【卷前,考生务必将自己的姓名、准考证号、考试科目用铅笔涂写在答题卡上。
2.每小题选出答案后,用铅笔把答题卡上对应題目的答案标号涂黑,如需玫动,用橡皮擦
擦千净后,再涂选其它答案,不准答在试题卷上。
3.考试结束后,将答题卡交回。
一、单项选择题:本题共7小题,每小题4分,共28分。在每小题给出的四个选项中,只有一项
是符合题目要求的。
1.人类对原子结构的认识经历了一段漫长的时期,其中提出原子的“核式结构模型”,被称为
“近代原子核物理之父”的物理学家是
A.汤姆孙
B.卢瑟福
C.玻尔
D.密立根
2.做简谐运动的物体,当物体的位移为正值时,下列说法正确的是
A.速度一定为正值,回复力一定为正值
B.速度一定为负值,回复力一定为负值
C.速度不一定为正值,回复力一定为正值
i/A
D.速度不一定为正值,回复力一定为负值
3.如图是某交变电流的i-t图像,这一交变电流的电流有效值为
A.10A
B.3A
C.32A
D.25A
高二物理试题第1页(共6页)
4.如图,一束光从真空中沿半径射入半球形玻璃砖,在0点分为两束单色光a、b。单色光a、b在
真空中的波长分别为入。、入6,该玻璃对单色光a、b的折射率分别为m。,6,0为玻璃砖球心。
则下列说法正确的是
A.入。>A6,na>ng
B.入,>入h,na
D.入。<入6,na
通量随时间变化的规律如图所示。已知π取3.14,下列说法
t匝/Wb
正确的
0.02
A.正弦式交流电的频率为5Hz
B.t=0.005s时,线圈中感应电动势达到最大值
C.线圈中感应电动势的最大值为314V
D.1s内电流方向变换50次
6.如图是LC振荡电路和通过点Q的电流随时间变化的规律。若把流过点Q向右的电流规
定为正方向,则下列说法正确的是
A.在t1~12内,电容器C在放电
B.在1~2内,电容器C上极板带正电
C.在t1~2内,电场能正在转化为磁场能
D.在~t2内,点Q的电势比点P的高
7.如图是电容式位移传感器的简化原理图,1为与被测物体相连的动极板,2为平行板电容器
的静止极板(一般称为定极板),1和2之间充满空气的间隙随着物体的位移而发生改变。
已知两极板分别带上等量异种电荷且电荷量恒定不变,则下列说法正确的是
A.被测物体向上移动,极板间的电势差增大
被测物体
B.被测物体向上移动,极板间的电势差减小
C.被测物体向下移动,极板间的场强增大
D.被测物体向下移动,极板间的场强减小
高二物理试题第2页(共6页)